Net Annual Change in the Surface Storage

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A 400 hectares sub-catchment receives 1100 mm annual rainfall and generates 600 m3 of average daily runoff from the sub-catchment.

If there is no water flow into the sub-catchment, what would be the net annual change in the surface storage, considering evapotranspiration and infiltration as 42% and 36% of precipitation?

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1 Answer

  1. since 10000 m^(2 )=1 HA ;
    (400*10000)*thus*area in m^2;
                                4000000
    area*times*length = volume;
                       area times length = volume
    (4*10^6*1.1)*total*annual*volume;
                                         6
                             4.4000000 10 
    considering*percentage*loses and adding*up;
               considering percentage loses and adding up
    36*loss*thats*total*percentage+42;
                                   78
    4.4*(1-.78)*10^6*what*is*left in the*bodie;
                                          5
                             9.68000000 10 
    total*annual*loss*of*run*off;
    (600*365.25)*what*is*lost in cubic*meters;
                                         5
                             2.1915000 10 
    (9.68-2.1915)*10^5*what*is*left;
                                          5
                            7.488500000 10 
    ` answer is 7.4885*10`^5*m^3;